简单的博弈。巨水。
求满足条件K mod (L+1)=0的最小L。
CO
/*
PROGRAM: $PROGRAM
AUTHOR: Su Jiao
DATE: 2010-3-18
DESCRIPTION:
$DESCRIPTION
*/
#include <iostream>
using std::cin;
using std::cout;
#include <fstream>
using std::ifstream;
using std::ofstream;
#include <sstream>
using std::stringstream;
using std::endl;
#include <vector>
using std::vector;
#include <string>
using std::string;
#include <stack>
using std::stack;
#include <queue>
using std::queue;
#include <map>
using std::map;
using std::pair;
using std::make_pair;
#include <algorithm>
using std::sort;
#include <cassert>
//using std::assert;
class Application
{
int K,L;
public:
Application()
{
cin>>K;
}
int run()
{
//K%(L+1)=0
for (L=2;L<K;L++)
if (!(K%(L+1))) break;
cout<<L%K<<endl;
return 0;
}
};
int main()
{
Application app;
return app.run();
}