本来挺水的题,却把我水惨了。
注意(我就是因此被水):用01串存一个节点的位置时,若深度为N,则编号0到2^N-1(满二叉树),也就是说题目中的Ep和Dp要减个一。
CO
/*
PROGRAM: $PROGRAM
AUTHOR: Su Jiao
DATE: 2010-4-12
DESCRIPTION:
$DESCRIPTION
*/
#include <iostream>
using std::cin;
using std::cout;
#include <fstream>
using std::ifstream;
using std::ofstream;
#include <sstream>
using std::stringstream;
using std::endl;
#include <vector>
using std::vector;
#include <string>
using std::string;
#include <stack>
using std::stack;
#include <queue>
using std::queue;
using std::priority_queue;
#include <set>
using std::set;
#include <map>
using std::map;
using std::pair;
using std::make_pair;
#include <algorithm>
using std::sort;
#include <cassert>
//using std::assert;
class Application
{
typedef int bit;
bit D,E,F,Dp,Ep,H;
static bit abs(bit a)
{
return a>=0?a:-a;
}
public:
Application()
{
cin>>D>>E>>F>>Dp>>Ep>>H;
}
int run()
{
bit cut=(~0);
bit need=0;
for (;;cut<<=1,need++)
if (((Dp-1)&cut)==((Ep-1)&cut))
{
if (D>=need&&E>=need) need=abs(D-E);
else need=abs(D-need)+abs(E-need);
if (need<=H) cout<<“YES”<<endl;
else cout<<“NO”<<endl;
break;
}
return 0;
}
};
int main()
{
Application app;
return app.run();
}