图论,在图中找尽可能多的环,且一个环的边的集合不是其它环的边的集合的子集。
然后,具体操作有看题解,所以我没必要讲了。
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/*
PROGRAM: $PROGRAM
AUTHOR: Su Jiao
DATE: 2010-4-10
DESCRIPTION:
$DESCRIPTION
*/
#include <iostream>
using std::cin;
using std::cout;
#include <fstream>
using std::ifstream;
using std::ofstream;
#include <sstream>
using std::stringstream;
using std::endl;
#include <vector>
using std::vector;
#include <string>
using std::string;
#include <stack>
using std::stack;
#include <queue>
using std::queue;
#include <map>
//using std::map;
using std::pair;
using std::make_pair;
#include <algorithm>
using std::sort;
#include <cassert>
//using std::assert;
class Application
{
int N,M;
vector<vector<bool> > map;
vector<vector<bool> > spaning_tree;
vector<bool> visited;
vector<int> path;
void dfs(int node)
{
visited[node]=true;
for (int i=0;i<N;i++)
if (map[node][i]&&(!visited[i]))
{
map[node][i]=false;
map[i][node]=false;
spaning_tree[node][i]=true;
spaning_tree[i][node]=true;
dfs(i);
}
}
void print(int node,const int& end)
{
if (!visited[node])
{
visited[node]=true;
path.push_back(node);
if (node==end)
{
cout<<path.size();
for (int i=0;i<path.size();i++) cout<<” “<<path[i]+1;
cout<<endl;
}
for (int i=0;i<N;i++)
if (spaning_tree[node][i])
print(i,end);
path.pop_back();
visited[node]=false;
}
}
public:
Application()
{
cin>>N>>M;
map.resize(N,vector<bool>(N,false));
for (int i=0;i<M;i++)
{
int u,v;
cin>>u>>v;
map[u-1][v-1]=map[v-1][u-1]=true;
}
}
int run()
{
spaning_tree.resize(N,vector<bool>(N,false));
visited.resize(N,false);
int part=0;
for (int i=0;i<N;i++)
if (!visited[i]) dfs(i),part++;
cout<<M-N+part<<endl;
visited=vector<bool>(N,false);
for (int i=0;i<N;i++)
for (int j=i+1;j<N;j++)
if (map[i][j])
print(i,j);
return 0;
}
};
int main()
{
Application app;
return app.run();
}