看了题解做的,题解大意是,DFS标记边的时候依次标1到M,这样任何一个点连到的边若超过1条,就必定有两条的标号相差1。所以满足条件(并且一定有解,所以输NO骗分是无用的)。
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/*
PROGRAM: $PROGRAM
AUTHOR: Su Jiao
DATE: 2010-3-22
DESCRIPTION:
$DESCRIPTION
*/
#include <iostream>
using std::cin;
using std::cout;
#include <fstream>
using std::ifstream;
using std::ofstream;
#include <sstream>
using std::stringstream;
using std::endl;
#include <vector>
using std::vector;
#include <string>
using std::string;
#include <stack>
using std::stack;
#include <queue>
using std::queue;
#include <set>
using std::set;
#include <map>
using std::map;
using std::pair;
using std::make_pair;
#include <algorithm>
using std::sort;
#include <cassert>
//using std::assert;
class Application
{
static const int NOMARK=-1;
int N,M;
vector<pair<pair<int,int>,int> > flight;
void dfs(int node,int& mark)
{
for (int i=0;i<M;i++)
{
if (flight[i].second==NOMARK)
{
if (flight[i].first.first==node)
{
flight[i].second=mark;
mark++;
dfs(flight[i].first.second,mark);
}
if (flight[i].first.second==node)
{
flight[i].second=mark;
mark++;
dfs(flight[i].first.first,mark);
}
}
}
}
public:
Application()
{
cin>>N>>M;
flight.resize(M);
for (int i=0;i<M;i++)
{
cin>>flight[i].first.first
>>flight[i].first.second;
flight[i].second=NOMARK;
}
}
int run()
{
int mark=1;
for (int i=1;i<=N;i++)
dfs(i,mark);
cout<<“YES”<<endl;
for (int i=0;i<M;i++)
cout<<flight[i].second<<char(i+1==M?’\n’:’ ‘);
return 0;
}
};
int main()
{
Application app;
return app.run();
}