看了题解做的,不好讲。主要思路就是逐步降低问题规模,一直降到m,n都很小,和3有关系。然后就得到了下面的程序。恩,还是不太懂。
OCDE:
/*
PROGRAM: $PROGRAM
AUTHOR: Su Jiao
DATE: 2010-3-27
DESCRIPTION:
$DESCRIPTION
*/
#include <iostream>
using std::cin;
using std::cout;
#include <fstream>
using std::ifstream;
using std::ofstream;
#include <sstream>
using std::stringstream;
using std::endl;
#include <vector>
using std::vector;
#include <string>
using std::string;
#include <stack>
using std::stack;
#include <queue>
using std::queue;
#include <set>
using std::set;
#include <map>
using std::map;
using std::pair;
using std::make_pair;
#include <algorithm>
using std::sort;
#include <cassert>
//using std::assert;
class Application
{
int M,N;
public:
Application()
{
cin>>M>>N;
}
int run()
{
if (M==1||N==1) cout<<(M+N)/2<<endl;
else cout<<((M*N)%3?1:2)<<endl;
return 0;
}
};
int main()
{
Application app;
return app.run();
}